A cell of some bacteria divides into two cells every 10 minutes.The initial population is 4 bacteria. Hint: The calculation will be easier if you let the unit of time be 10 minutes, so that one hour is (60/10) units of time.
a. Find the population after t hours.
b. Find the population after 4 hours.
c. Find the population after 16 hours.
2.A bacteria culture starts with 700 bacteria and grows at a rate propotional to its size.After 2 hours there are 1400 bacteria.
a. Find the population after t hours
b. Find the population after 5 hours.
c. When will the population reach 1850 ?
Find the population after t hours.?
1) P = 4*2^t, where t=1 means 10 minutes, t=2 means 20 min.
Check: at t=0, there were 4. After 10 minutes, there will be 4*2 = 8, after 20 minutes there will be 4*2^2 = 16.
a) pop after T hours means 6 units of time*T or
P = 4*2^(6T), T in hours.
b) Pop after 4 hours means
P = 4*2^(24).
Do the rest for this problem.
2.A bacteria culture starts with 700 bacteria and grows at a rate propotional to its size.After 2 hours there are 1400 bacteria.
dP/dt = aP, separate
dP/P = a dt, integrate
ln(P) = at + C, so
e^(at+C) = P or
Ce^(at) = P. At t=0, there were 700, so C = 700, or
700 e^(at) = P. at t = 2 hours, we have 1400, so
700 e^(2a) = 1400, div by 700 or
e^(2a) = 2, take ln of both sides, or
2a = ln(2), so
a = ln(2)/2. So formula is
700 e^(t*ln(2)/2) = P.
Do the rest.
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