The equation of motion of a particle is s= 2t^3 - 9t^2 + 5t + 7 where is in meters and is in seconds.
a) Find the velocity as a function of t.
(b) Find the acceleration as a function of t
The equation of motion of a particle is , where is in meters and is in seconds.
(a) Find the velocity as a function of f .
(b) Find the acceleration as a function of .
(c) Find the acceleration (in m/s^2) after 3 s.
Find the velocity as a function of f?
(a) velocity, v = ds/dt
hence, v = 6t^2 - 18t + 5
(b) acceleration, a = dv/dt
a = 12t - 18
(c) acceleration, A after 3s can be found by substituting t = 3s into the equation a = 12t - 18 (answer for (b))
hence, A = 12(3) - 18 = 36 - 18 = 18 ms^2
btw, u're repeating the same question, and yet the 2nd (a) that u put down does not make sense, firstly, function of f when f is never given/doesnt appear in the question?
Reply:(a) v(t) = d s(t) / dt = 3.2t^2 - 2.9t + 5 = 6t^2 -18t +5
(b) a(t) = d v(t)/ dt = 2.6t -18 =12t -18
(c) a(3) = 12(3) - 18 = 18 m/s^2
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