I'm new to Texas and I'm having a hard time finding a job, now before you all jump down my throat for smoking pot, don't judge someone by something that they do or don't do. My question is, are there any temp agencies or companies that just won't piss test me or at least give me some notice before they do? I smoke to deal with life and my husbands injuries from being overseas, I don't "abuse" it, if I could use medical pot in Texas I'd be over qualified for it for sure. I just was searching online for Non Drug Testing Companies and only found a list from 2002, which isn't recent enough. It's bad enough I'm not Bi-Lingual and living in Texas.... I've found a few sites that don't list Bi-Lingual jobs which is a bonus, but can't seem to find a site that lists jobs that won't require a drug test to get hired.
Trust me I know I should quit till I find a job, but I've been looking for almost a year now and can't find a freaking thing.
ANY HELP WOULD BE GREAT, Thanks again :-)
How to find a NON DRUG TESTING job in texas.?
why don't you just quit doing drugs?
Reply:gas stations, restaurants, retail, delivering newspapers, etc don't drug test.
Start your own business.
Reply:A lot of companies do now. try a waitressing job in a strip club (talk about good money), temp agency the ones that pay by the day.
Reply:until you can get off the dope, McDonald's is hiring
dedicated server
Friday, November 13, 2009
Given the X intercepts and vertex, find the equation of the parabola?
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola?
Given the parabola ax^2 + bx + c = 0 = f(x)
If you have the intercepts, x1 and x2, you have the roots of the equation, such that (x -x1)(x-x2)=f(x)
If you have the vertex (xv,yv), this is the point at which 2a xv + b = 0
Reply:2x=y
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola
Given the X intercepts and vertex, find the equation of the parabola?
Given the parabola ax^2 + bx + c = 0 = f(x)
If you have the intercepts, x1 and x2, you have the roots of the equation, such that (x -x1)(x-x2)=f(x)
If you have the vertex (xv,yv), this is the point at which 2a xv + b = 0
Reply:2x=y
Search Find (Ctrl F) only searches/finds words. What about symbols (in blueprints,etc.)?
Is there any program that could search/find ( Ctrl F) key symbols (not just words) in a drawing (ei,electrical, HVAC,etc.)This way it would "find"all the common symbols for estimates. Example, I want to find all the "thermostats" in a particular drawing, instead of looking at the drawing and counting/highlighting each one, than adding them, the search/find would list them. Perhaps upload symbols (not only words or numbers). Make sense?
Search Find (Ctrl F) only searches/finds words. What about symbols (in blueprints,etc.)?
I understand what you mean, but it probably depends on what program you are using. Programs specifically designed for designing stuff might have a "summary of parts" of some sort. If they don't there probably isn't a way.
computer networking
Search Find (Ctrl F) only searches/finds words. What about symbols (in blueprints,etc.)?
I understand what you mean, but it probably depends on what program you are using. Programs specifically designed for designing stuff might have a "summary of parts" of some sort. If they don't there probably isn't a way.
computer networking
In finding a segment of a circle, how do you find the height of the triangle?
When finding the segment of a circle you must find the triangle from the number of degrees, then you have to find the height of the triangle in order for it to work. I have a circle with 60 degrees and 12m radius, how do I find the height to these triangles?? Is there a formula you can provide me with?
In finding a segment of a circle, how do you find the height of the triangle?
cosine/radius
sine/radius
a2+B2=C2
In finding a segment of a circle, how do you find the height of the triangle?
cosine/radius
sine/radius
a2+B2=C2
1.Find the vertical asymptote of the rational function: f(x) = 3x-12 divided by 4x-2?
1.Find the vertical asymptote of the rational function: f(x) = 3x-12 divided by 4x-2
a. x = 1/2
b. x = 3/4
c. x = 2
d. x = 4
2. For the following equation, find the interval(s) where f(x) less than 0.
f(x) = 1 Divided by x^2-2x-8
a. (-4, 2)
b. (-2, 4)
c. (2, 4)
d. (2, 8)
3. Find the quotient and remainder of f(x) = x^3 - 4x^2 + 5x + 5 divided by p(x) = x - 1.
a. x^2 + 2x + 2; 7
b. x^2 - 3x + 3; -5
c. x^2 - 3x + 2; 7
d. x^2 - 2x + 3; -5
4. The polynomial f(x) divided x - 3 results in a quotient of x^2+3x-5 with a remainder of 2. Find f(3).
a) -5
b) -2
c) 2
d) 3
5. Let f(x) = x^3 - 8x^2 + 17x - 9. Use the factor theorem to find other solutions to f(x) - f(1) = 0, besides x = 1.
a) -2, 5
b) 2, -3
c) 2, 5
d) 2, 10
1.Find the vertical asymptote of the rational function: f(x) = 3x-12 divided by 4x-2?
1. Vertical asymptotes occur when the denominator is zero, i.e. when 4x-2 = 0, so at x = 1/2.
2. Factor the denominator x^2-2x-8 = (x-4)(x+2). Draw a number line and mark the points where the factors are zero, i.e. at x= 4 and -2. This divides the number line into three regions (a) x %26lt; -2 (b) -2 %26lt; x %26lt;4 and (c) x %26gt; 4.
When x %26lt; -2, (x-4) is negative and (x+2) is also negative so (x-4)(x+2) wil be positive, hence f(x) %26gt;0.
When -2 %26lt; x %26lt; 4, (x-4) is negative and (x+2) is positive so (x-4)(x+2) wil be negative, hence f(x) %26lt;0.
When x %26gt; 4, (x-4) is positive and (x+2) is also positive so (x-4)(x+2) wil be positive, hence f(x) %26gt;0.
3. What is x^3 divided by x? Answer is x^2 and multiplying p(x) by x^2 gives x^3-x^2. Subtract this from f(x) to get -3x^2+5x+5. Continue the division by mulitplying p(x) by -3x (to get rid of the -3x^2) to give -3x^2+3x and subtract from -3x^2+5x+5. This leaves 2x+5 and multiplying p(x) by 2 gives 2x-2; subtracting from 2x+5 leaves remainder 5-(-2)=7. Quotient is x^2-3x+2, remainder 7.
4. Straightforward application of remainder theorem, i.e. remainder after a polynomial f(x) is divided by (x-a) is f(a). So f(3) is 2.
5. Again using the factor (or remainder) theorem, we calculate f(2) = 2^3-8*2^2+17*2-9 = 8-32+34-9 = 1,
f(5) = 5^3-8*5^2+17*5-9 = 125-200+85-9 = 1 so answer is c.
a. x = 1/2
b. x = 3/4
c. x = 2
d. x = 4
2. For the following equation, find the interval(s) where f(x) less than 0.
f(x) = 1 Divided by x^2-2x-8
a. (-4, 2)
b. (-2, 4)
c. (2, 4)
d. (2, 8)
3. Find the quotient and remainder of f(x) = x^3 - 4x^2 + 5x + 5 divided by p(x) = x - 1.
a. x^2 + 2x + 2; 7
b. x^2 - 3x + 3; -5
c. x^2 - 3x + 2; 7
d. x^2 - 2x + 3; -5
4. The polynomial f(x) divided x - 3 results in a quotient of x^2+3x-5 with a remainder of 2. Find f(3).
a) -5
b) -2
c) 2
d) 3
5. Let f(x) = x^3 - 8x^2 + 17x - 9. Use the factor theorem to find other solutions to f(x) - f(1) = 0, besides x = 1.
a) -2, 5
b) 2, -3
c) 2, 5
d) 2, 10
1.Find the vertical asymptote of the rational function: f(x) = 3x-12 divided by 4x-2?
1. Vertical asymptotes occur when the denominator is zero, i.e. when 4x-2 = 0, so at x = 1/2.
2. Factor the denominator x^2-2x-8 = (x-4)(x+2). Draw a number line and mark the points where the factors are zero, i.e. at x= 4 and -2. This divides the number line into three regions (a) x %26lt; -2 (b) -2 %26lt; x %26lt;4 and (c) x %26gt; 4.
When x %26lt; -2, (x-4) is negative and (x+2) is also negative so (x-4)(x+2) wil be positive, hence f(x) %26gt;0.
When -2 %26lt; x %26lt; 4, (x-4) is negative and (x+2) is positive so (x-4)(x+2) wil be negative, hence f(x) %26lt;0.
When x %26gt; 4, (x-4) is positive and (x+2) is also positive so (x-4)(x+2) wil be positive, hence f(x) %26gt;0.
3. What is x^3 divided by x? Answer is x^2 and multiplying p(x) by x^2 gives x^3-x^2. Subtract this from f(x) to get -3x^2+5x+5. Continue the division by mulitplying p(x) by -3x (to get rid of the -3x^2) to give -3x^2+3x and subtract from -3x^2+5x+5. This leaves 2x+5 and multiplying p(x) by 2 gives 2x-2; subtracting from 2x+5 leaves remainder 5-(-2)=7. Quotient is x^2-3x+2, remainder 7.
4. Straightforward application of remainder theorem, i.e. remainder after a polynomial f(x) is divided by (x-a) is f(a). So f(3) is 2.
5. Again using the factor (or remainder) theorem, we calculate f(2) = 2^3-8*2^2+17*2-9 = 8-32+34-9 = 1,
f(5) = 5^3-8*5^2+17*5-9 = 125-200+85-9 = 1 so answer is c.
Ways to find a lost camera? PLEASE HELP?
I lost a Digital Camera at a Museum in New Work.
It has much sentimental value and it means a lot to me.
I tried to find it right after I lost it.
But I cannot find it :(
I tried to:
1. I asked the Lost %26amp; Found department of the museum and they just said no camera was found. I keep calling and having same response.
2. I posted a notice on craigslist.org %26amp; some other website and there is still no response now.
3. I also looked over the stores which sell used camera nearby the museum. Until now, I could not find it.
But I will keep searching the used camera stores.
Can anyone suggest ways for me to find it, please?
PLEASE HELP
Ways to find a lost camera? PLEASE HELP?
sorry, but that's like losing a 20 dollar bill on the street. Just hope that the finder of it is using and caring for it in a gingerly manner. I mean, not breaking it or whatever.
Reply:its gone.
It might have been taken by some tourist .....
I lost a very expensive Ebel watch in Disneyland, made a report at lost and found but never heard from them .........
Reply:dont lose it in the first place ya silly goose....or just pray to bruce willis and if he deems it so u shall find said camera
Reply:pray to saint anthony i swear it will work! works for me everytime!
Reply:I'm sorry you lost your camera. No doubt someone picked it up and its gone for good.
Yet another reason to keep your camera tethered to your wrist or hanging around your neck at all times. You must remember that there are a lot of people out there who are waiting for you to leave your purse open or lay your camera down and turn away. BOOM! Its gone!
It has much sentimental value and it means a lot to me.
I tried to find it right after I lost it.
But I cannot find it :(
I tried to:
1. I asked the Lost %26amp; Found department of the museum and they just said no camera was found. I keep calling and having same response.
2. I posted a notice on craigslist.org %26amp; some other website and there is still no response now.
3. I also looked over the stores which sell used camera nearby the museum. Until now, I could not find it.
But I will keep searching the used camera stores.
Can anyone suggest ways for me to find it, please?
PLEASE HELP
Ways to find a lost camera? PLEASE HELP?
sorry, but that's like losing a 20 dollar bill on the street. Just hope that the finder of it is using and caring for it in a gingerly manner. I mean, not breaking it or whatever.
Reply:its gone.
It might have been taken by some tourist .....
I lost a very expensive Ebel watch in Disneyland, made a report at lost and found but never heard from them .........
Reply:dont lose it in the first place ya silly goose....or just pray to bruce willis and if he deems it so u shall find said camera
Reply:pray to saint anthony i swear it will work! works for me everytime!
Reply:I'm sorry you lost your camera. No doubt someone picked it up and its gone for good.
Yet another reason to keep your camera tethered to your wrist or hanging around your neck at all times. You must remember that there are a lot of people out there who are waiting for you to leave your purse open or lay your camera down and turn away. BOOM! Its gone!
Can't find the right car?
I am having trouble finding the right car. I really like the Mazda 6 sedan, but I can't really find one that I love. I found one that was a great color, but the interior was tan. I think tan interior looks kind of cheap. I found an awesome yellow one with black leather interior, but on carfax it had 14 reports, whatever that is. My dad says that isn't good. We don't know exactly what the reports are. I just can't find the one I want around my town. We searched up to 100 miles away, and there weren't too many I liked. It may sound like I am whining, but I am not. I just want to find the perfect car for me. Any ideas on what to do?
Can't find the right car?
Carfax reports are not necessarily a bad thing. Reports are simply like change of title, or it passed emissions test. If you really like it I say go ahead and buy a report from Carfax and find out what the reports are!
Reply:Well to begin with 14 reports does not mean bad news. If you don't know how Car-fax works then don't use it.Second pick a better car.
Reply:i agree with just me pick another car. maybe you didnt know or just dont care but mazda is a branch from ford. personally ford sux. i would get a gm vehicle you might not care or anything but you could also make your own mazda online and make it the way you want to and then it will be shipped to your nearest mazda dealer
Reply:Go on msn or yahoo autos, go to decision making guides, fill your answers and see what pops up
Reply:get a limo!
Reply:Don't be too idealistic about your fisrt car, afterall, it is your first car and you ain't picking a boyfriend..Chances are you'll have many cars in your life, so just try driving around in any economical used car and get more driving experience. By the secong car, you'll know better..
Reply:keep looking hun
gold teeth
Can't find the right car?
Carfax reports are not necessarily a bad thing. Reports are simply like change of title, or it passed emissions test. If you really like it I say go ahead and buy a report from Carfax and find out what the reports are!
Reply:Well to begin with 14 reports does not mean bad news. If you don't know how Car-fax works then don't use it.Second pick a better car.
Reply:i agree with just me pick another car. maybe you didnt know or just dont care but mazda is a branch from ford. personally ford sux. i would get a gm vehicle you might not care or anything but you could also make your own mazda online and make it the way you want to and then it will be shipped to your nearest mazda dealer
Reply:Go on msn or yahoo autos, go to decision making guides, fill your answers and see what pops up
Reply:get a limo!
Reply:Don't be too idealistic about your fisrt car, afterall, it is your first car and you ain't picking a boyfriend..Chances are you'll have many cars in your life, so just try driving around in any economical used car and get more driving experience. By the secong car, you'll know better..
Reply:keep looking hun
gold teeth
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