Find......?

e^∫[1/(2x - 4)] dx





Thanks.

Find......?
[1/(2x-4) ] dx = 1/2 [ 2/(2x-4) ] dx


integral of [1/(2x-4)] dx = 1/2 integral of [ 2/(2x-4)] dx


integral of [1/(2x-4)] dx = (1/2)* ln(2x-4)


e^{integral of [1/(2x-4)] dx} = e^ [(1/2)*ln(2x-4)]





the right side of the equation simplifies to:


e^ {ln[(2x-4)^(1/2)]}


(2x-4)^(1/2)