1. find x and y intercepts for the line that contain the points 4,3 and -8,7?

i have more questions


2. Find the equation of the line perpendicular to 2x + 5y = 10 and passes through the point (8,9)


3. What is the slope of the line perpendicular to the line that passes through the points (4, 2) and (-5, -7)


5.Find a function whose inverse is not a function


7Find the equation of the line that passes through the points (17, 2) and ( -3, 0)


8.One number is 876.1 more than twice the other. If the sum of the two numbers is 2005.45, find the larger of the two numbers.


9.The three vertices of a triangle are (3, 7), (6, -1), and (-3, -4). Find the sum of the slopes of the three sides of the triangle. Write your answer as a reduced fraction.

1. find x and y intercepts for the line that contain the points 4,3 and -8,7?
1.


So we need to find the equation of the line first


x1=4 ,y1=3, x2=-8, y2=7


i) find the gradient (y2-y1)/(x2-x1)


(7-3)/(-8-4)= 4/-12=-1/3=m





ii) Use the point gradient formula y-y1=m(x-x1)


y-3=-1/3(x-4)


3y-9=-1(x-4)


3y-9=-x+4


3y+x-13=0





x intercept is when y=0





0+x-13=0


x=13





y intercept is when x=0


3y-13=0


3y=13


y=13/3





2. Find the gradient of the given line. (this is the coeffiecient of x when y is the subject of the formula)





2x + 5y = 10


5y=10-2x


y=2-2/5x





the gradient is -2/5.





The gradient of the perpendicular line is the negative reciprocal of this (5/2)





We have a point (8,9) and a gradient (5/2) so use the point gradient formula again





y-9=5/2(x-8)


2y-18=5x-40


2y-5x+22=0





3.


The gradient of the line joining these two points is





(-7-2)/(-5-4)=-9/-9=1





The perpendicular gradient is then -1 (negative reciprocal) which is the slope of the perpendicualr line.





7) find gradient (0-2)/(-3-17)=-2/-20=1/10





y-2=1/10(x-17)


10y-20=x-17


10y-x-3=0





This is a start





Hope it helps