Help me find the volume....?

Answer the ones you can





1) Density= mass/volume


mass= .5 gram


volume= 6 liters


find density





2) Find the Volume for the Cone(v= 1/3 • π • r² • height)


height= 15 inches


diameter= 9 inches





3) Find the Volume for the Piramid (v= 1/3bh)


height= 9


base=42





4) Find the Volume for the Cylinder (v= π • r² • height)


volume= 15 inches/liters


diameter= 6





5) Sphere: (v= 4/3 • π • r³)


volume= 36


find the radius





Thank you.

Help me find the volume....?
1) Density is usually expressed in g/cm³, but we'll keep it in lilters:





m = 0.5 gm


V = 6l


D = m / V


D = 0.5 / 6


D = 0.0833 gm / l


¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯


2) h = 15in.


d = 9 in.


Find r;


r = d / 2


r = 9 / 2, or 4.5 in.


V = 1/3 π r² h


V = (3.14159 * (4.5)² * 15) / 3


V = (3.14159 * 20.25 * 15) / 3


V = 954.258 / 3


V = 318.086 cu. in.


¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯


3) The volume of a regular pyramid is V = 1/3(Base Area * Height), so your formula is wrong.





h = 9 units


b = 42 units


A = b²


A = 42²


A = 1746 sq. units


V = Ah / 3


V = (1746 * 9) / 3


V = 15714 / 3


V = 5238 cu. units


¯¯¯¯¯¯¯¯¯¯¯¯¯¯


4) You ask for the volume, but then you give it, so the problem is misstated.





5) V = 36 cu. units


V = 4/3 π r³, or (4 π r³) / 3


Solve for r:


Multiplying both sides by 3:


3V = 4 π r³


Dividing both sides by 4 π:


3V / 4 π = r³


Taking the cube root of both sides:


³√(3V / 4 π) = r, or


r = ³√(3V / 4 π)


r = ³√((3 * 36) / (4 * 3.14159))


r = ³√(108 / 12.5664)


r = ³√8.5943


r = 2.0483 units


¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
Reply:All you need is a calculator and a piece of paper and a pencil. There is no reason you can't solve these equations. All you do is plug in the numbers in the right place and solve for the missing variable using basic operations.





I will give you one hint. Pi = 3.14. Though most calculators have a pi button.