Find the percent of decrease; original price $27, new price $18 [25% or 33 1/3% or 66 2/3% or 75%?

find the range for 16,12,14,18,17,13, AND 17?





TEST SCORE FREQUENCY


100 2


95 3


90 7


85 8


80 7


75 3


find the mean for the above test score-frequency


find the median


find the mote

Find the percent of decrease; original price $27, new price $18 [25% or 33 1/3% or 66 2/3% or 75%?
33 1/3%





Median = 86
Reply:Percentage of decrease = difference in prices divided by the original price multiplied by 100.





OR





= [($27 - $18)/ $27] X 100





= $9/$27 X 100





= 0.333333... X 100





= 33.3333... or 33 1/3%


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Find the range for 16, 12, 14, 18, 17, 13, and 17?





The range is 12 to 18





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Test Score Frequency





100 2


95 3


90 7


85 8


80 7


75 3





Find the mean for the above test scores:


mean equals total of test scores divided by the number of items.





The total of all test scores is 2580; there are 30 samples so:





Mean = 2580/30 = 86





The Median is 90 %26amp; 85, since these two are the center measurements of the group.





The Mote is 85 since that was score with the highest frequency.